Base | Representation |
---|---|
bin | 10010010010111110000110… |
… | …01101011101000001001011 |
3 | 12021110100120221001011011021 |
4 | 21021133003031131001023 |
5 | 20233144202314323413 |
6 | 221323203554213311 |
7 | 11321553551035621 |
oct | 1111370315350113 |
9 | 167410527034137 |
10 | 40234233745483 |
11 | 11902274054a08 |
12 | 46197b7584237 |
13 | 195b0c214146b |
14 | 9d14c1003511 |
15 | 49b8b881318d |
hex | 2497c335d04b |
40234233745483 has 2 divisors, whose sum is σ = 40234233745484. Its totient is φ = 40234233745482.
The previous prime is 40234233745373. The next prime is 40234233745501. The reversal of 40234233745483 is 38454733243204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40234233745483 - 217 = 40234233614411 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40234233745483.
It is not a weakly prime, because it can be changed into another prime (40234233745583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20117116872741 + 20117116872742.
It is an arithmetic number, because the mean of its divisors is an integer number (20117116872742).
Almost surely, 240234233745483 is an apocalyptic number.
40234233745483 is a deficient number, since it is larger than the sum of its proper divisors (1).
40234233745483 is an equidigital number, since it uses as much as digits as its factorization.
40234233745483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23224320, while the sum is 52.
Adding to 40234233745483 its reverse (38454733243204), we get a palindrome (78688966988687).
The spelling of 40234233745483 in words is "forty trillion, two hundred thirty-four billion, two hundred thirty-three million, seven hundred forty-five thousand, four hundred eighty-three".
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