Base | Representation |
---|---|
bin | 10010010011001011000110… |
… | …00111001001001100000011 |
3 | 12021111000121012202101212211 |
4 | 21021211203013021030003 |
5 | 20233303000110211001 |
6 | 221330320214002551 |
7 | 11322221506163422 |
oct | 1111454307111403 |
9 | 167430535671784 |
10 | 40241211413251 |
11 | 11905224835a92 |
12 | 461b024346457 |
13 | 195b964928564 |
14 | 9d19839c92b9 |
15 | 49bb761ba351 |
hex | 2499631c9303 |
40241211413251 has 2 divisors, whose sum is σ = 40241211413252. Its totient is φ = 40241211413250.
The previous prime is 40241211413191. The next prime is 40241211413281. The reversal of 40241211413251 is 15231411214204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40241211413251 - 215 = 40241211380483 is a prime.
It is not a weakly prime, because it can be changed into another prime (40241211413281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20120605706625 + 20120605706626.
It is an arithmetic number, because the mean of its divisors is an integer number (20120605706626).
Almost surely, 240241211413251 is an apocalyptic number.
40241211413251 is a deficient number, since it is larger than the sum of its proper divisors (1).
40241211413251 is an equidigital number, since it uses as much as digits as its factorization.
40241211413251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 40241211413251 its reverse (15231411214204), we get a palindrome (55472622627455).
The spelling of 40241211413251 in words is "forty trillion, two hundred forty-one billion, two hundred eleven million, four hundred thirteen thousand, two hundred fifty-one".
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