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40243412131 = 1322333073329
BaseRepresentation
bin100101011110101100…
…011011110010100011
310211212122002011011121
4211132230123302203
51124404303142011
630253151553111
72623161234106
oct453654336243
9124778064147
1040243412131
11160813a219a
12797152b797
133a44629500
141d3aa5073d
1510a8068e71
hex95eb1bca3

40243412131 has 24 divisors (see below), whose sum is σ = 43919956080. Its totient is φ = 36856774656.

The previous prime is 40243412123. The next prime is 40243412149. The reversal of 40243412131 is 13121434204.

It is not a de Polignac number, because 40243412131 - 23 = 40243412123 is a prime.

It is a super-2 number, since 2×402434121312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40243412096 and 40243412105.

It is not an unprimeable number, because it can be changed into a prime (40243412431) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12087075 + ... + 12090403.

It is an arithmetic number, because the mean of its divisors is an integer number (1829998170).

Almost surely, 240243412131 is an apocalyptic number.

40243412131 is a deficient number, since it is larger than the sum of its proper divisors (3676543949).

40243412131 is a wasteful number, since it uses less digits than its factorization.

40243412131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3895 (or 3882 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 40243412131 its reverse (13121434204), we get a palindrome (53364846335).

The spelling of 40243412131 in words is "forty billion, two hundred forty-three million, four hundred twelve thousand, one hundred thirty-one".

Divisors: 1 13 169 233 307 3029 3329 3991 39377 43277 51883 71531 562601 775657 929903 1022003 10083541 12088739 13286039 131086033 172718507 238126699 3095647087 40243412131