Base | Representation |
---|---|
bin | 1011101101100111000… |
… | …10100010100001010011 |
3 | 1102110210000122021012012 |
4 | 11312303202202201103 |
5 | 23043201144300413 |
6 | 504514050253135 |
7 | 41034640462346 |
oct | 5666342424123 |
9 | 1373700567165 |
10 | 402444134483 |
11 | 145748249856 |
12 | 65bb58871ab |
13 | 2bc47b0a671 |
14 | 1569aa3045d |
15 | a70628b7a8 |
hex | 5db38a2853 |
402444134483 has 2 divisors, whose sum is σ = 402444134484. Its totient is φ = 402444134482.
The previous prime is 402444134467. The next prime is 402444134497. The reversal of 402444134483 is 384431444204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 402444134483 - 24 = 402444134467 is a prime.
It is a super-2 number, since 2×4024441344832 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 402444134483.
It is not a weakly prime, because it can be changed into another prime (402444134453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201222067241 + 201222067242.
It is an arithmetic number, because the mean of its divisors is an integer number (201222067242).
Almost surely, 2402444134483 is an apocalyptic number.
402444134483 is a deficient number, since it is larger than the sum of its proper divisors (1).
402444134483 is an equidigital number, since it uses as much as digits as its factorization.
402444134483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 589824, while the sum is 41.
Adding to 402444134483 its reverse (384431444204), we get a palindrome (786875578687).
The spelling of 402444134483 in words is "four hundred two billion, four hundred forty-four million, one hundred thirty-four thousand, four hundred eighty-three".
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