Base | Representation |
---|---|
bin | 10010010011101100001000… |
… | …00010100001111101110011 |
3 | 12021112201101000012222121221 |
4 | 21021312010002201331303 |
5 | 20234100304043040311 |
6 | 221342411534525511 |
7 | 11323420104256546 |
oct | 1111660402417563 |
9 | 167481330188557 |
10 | 40258943721331 |
11 | 119117a4200555 |
12 | 4622552966897 |
13 | 196052c56074a |
14 | 9d2786a5285d |
15 | 49c362ce7671 |
hex | 249d840a1f73 |
40258943721331 has 2 divisors, whose sum is σ = 40258943721332. Its totient is φ = 40258943721330.
The previous prime is 40258943721317. The next prime is 40258943721397. The reversal of 40258943721331 is 13312734985204.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40258943721331 - 211 = 40258943719283 is a prime.
It is a super-2 number, since 2×402589437213312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40258943721131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20129471860665 + 20129471860666.
It is an arithmetic number, because the mean of its divisors is an integer number (20129471860666).
Almost surely, 240258943721331 is an apocalyptic number.
40258943721331 is a deficient number, since it is larger than the sum of its proper divisors (1).
40258943721331 is an equidigital number, since it uses as much as digits as its factorization.
40258943721331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 52.
The spelling of 40258943721331 in words is "forty trillion, two hundred fifty-eight billion, nine hundred forty-three million, seven hundred twenty-one thousand, three hundred thirty-one".
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