Base | Representation |
---|---|
bin | 10010010100011011000100… |
… | …00101000000110000111011 |
3 | 12021122010102020112002110121 |
4 | 21022031202011000300323 |
5 | 20240003411300001303 |
6 | 221402140302554111 |
7 | 11325301431055513 |
oct | 1112154205006073 |
9 | 167563366462417 |
10 | 40284143750203 |
11 | 11921455a3a1a1 |
12 | 4627406298937 |
13 | 1962a17361432 |
14 | 9d3a977c8843 |
15 | 49cd3a32c9bd |
hex | 24a362140c3b |
40284143750203 has 2 divisors, whose sum is σ = 40284143750204. Its totient is φ = 40284143750202.
The previous prime is 40284143750143. The next prime is 40284143750239. The reversal of 40284143750203 is 30205734148204.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40284143750203 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40284143750203.
It is not a weakly prime, because it can be changed into another prime (40284143750273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20142071875101 + 20142071875102.
It is an arithmetic number, because the mean of its divisors is an integer number (20142071875102).
Almost surely, 240284143750203 is an apocalyptic number.
40284143750203 is a deficient number, since it is larger than the sum of its proper divisors (1).
40284143750203 is an equidigital number, since it uses as much as digits as its factorization.
40284143750203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 43.
Adding to 40284143750203 its reverse (30205734148204), we get a palindrome (70489877898407).
The spelling of 40284143750203 in words is "forty trillion, two hundred eighty-four billion, one hundred forty-three million, seven hundred fifty thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •