403053141513053 has 4 divisors (see below), whose sum is σ = 408729946323168. Its totient is φ = 397376336702940.

The previous prime is 403053141513041. The next prime is 403053141513101. The reversal of 403053141513053 is 350315141350304.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 403053141513053 - 2²⁰ = 403053140464477 is a prime.

It is a super-2 number, since 2×403053141513053² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 403053141512998 and 403053141513016.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (403053141513553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2838402404951 + ... + 2838402405092.

It is an arithmetic number, because the mean of its divisors is an integer number (102182486580792).

Almost surely, 2^{403053141513053} is an apocalyptic number.

It is an amenable number.

403053141513053 is a deficient number, since it is larger than the sum of its proper divisors (5676804810115).

403053141513053 is an equidigital number, since it uses as much as digits as its factorization.

403053141513053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5676804810114.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 403053141513053 its reverse (350315141350304), we get a palindrome (753368282863357).

The spelling of 403053141513053 in words is "four hundred three trillion, fifty-three billion, one hundred forty-one million, five hundred thirteen thousand, fifty-three".