Base | Representation |
---|---|
bin | 111010101010010010011… |
… | …110001100100110111011 |
3 | 112021101001211220121121012 |
4 | 322222102132030212323 |
5 | 1012021231444310042 |
6 | 12323513441504135 |
7 | 564145216463345 |
oct | 72522236144673 |
9 | 15241054817535 |
10 | 4031136713147 |
11 | 1314660646055 |
12 | 55131764204b |
13 | 233199826c5b |
14 | dd172722295 |
15 | 6ecd47bce82 |
hex | 3aa9278c9bb |
4031136713147 has 2 divisors, whose sum is σ = 4031136713148. Its totient is φ = 4031136713146.
The previous prime is 4031136713143. The next prime is 4031136713159. The reversal of 4031136713147 is 7413176311304.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4031136713147 - 22 = 4031136713143 is a prime.
It is not a weakly prime, because it can be changed into another prime (4031136713141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015568356573 + 2015568356574.
It is an arithmetic number, because the mean of its divisors is an integer number (2015568356574).
Almost surely, 24031136713147 is an apocalyptic number.
4031136713147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4031136713147 is an equidigital number, since it uses as much as digits as its factorization.
4031136713147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 127008, while the sum is 41.
The spelling of 4031136713147 in words is "four trillion, thirty-one billion, one hundred thirty-six million, seven hundred thirteen thousand, one hundred forty-seven".
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