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4031256824393 is a prime number
BaseRepresentation
bin111010101010011001101…
…000011000101001001001
3112021101101012220220020212
4322222121220120221021
51012022003221340033
612323533412130505
7564151205430041
oct72523150305111
915241335826225
104031256824393
111314712423447
1255134b906a35
132331b868c6b6
14dd18466a721
156ece00e6748
hex3aa99a18a49

4031256824393 has 2 divisors, whose sum is σ = 4031256824394. Its totient is φ = 4031256824392.

The previous prime is 4031256824369. The next prime is 4031256824407. The reversal of 4031256824393 is 3934286521304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2768752897849 + 1262503926544 = 1663957^2 + 1123612^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4031256824393 is a prime.

It is a super-3 number, since 3×40312568243933 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4031256824293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015628412196 + 2015628412197.

It is an arithmetic number, because the mean of its divisors is an integer number (2015628412197).

Almost surely, 24031256824393 is an apocalyptic number.

It is an amenable number.

4031256824393 is a deficient number, since it is larger than the sum of its proper divisors (1).

4031256824393 is an equidigital number, since it uses as much as digits as its factorization.

4031256824393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3732480, while the sum is 50.

The spelling of 4031256824393 in words is "four trillion, thirty-one billion, two hundred fifty-six million, eight hundred twenty-four thousand, three hundred ninety-three".