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40313453331497 is a prime number
BaseRepresentation
bin10010010101010001101010…
…00100001100010000101001
312021201221001212200002102112
421022220311010030100221
520240443423023101442
6221423424513012105
711330356645310033
oct1112506504142051
9167657055602375
1040313453331497
1111932926488455
124631025b54035
131965708690248
149d5278270c53
1549d9a3528082
hex24aa3510c429

40313453331497 has 2 divisors, whose sum is σ = 40313453331498. Its totient is φ = 40313453331496.

The previous prime is 40313453331451. The next prime is 40313453331517. The reversal of 40313453331497 is 79413335431304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37012269580441 + 3301183751056 = 6083771^2 + 1816916^2 .

It is a cyclic number.

It is not a de Polignac number, because 40313453331497 - 210 = 40313453330473 is a prime.

It is a super-2 number, since 2×403134533314972 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40313453331797) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20156726665748 + 20156726665749.

It is an arithmetic number, because the mean of its divisors is an integer number (20156726665749).

Almost surely, 240313453331497 is an apocalyptic number.

It is an amenable number.

40313453331497 is a deficient number, since it is larger than the sum of its proper divisors (1).

40313453331497 is an equidigital number, since it uses as much as digits as its factorization.

40313453331497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 50.

The spelling of 40313453331497 in words is "forty trillion, three hundred thirteen billion, four hundred fifty-three million, three hundred thirty-one thousand, four hundred ninety-seven".