Base | Representation |
---|---|
bin | 111010101011001000011… |
… | …000010010100110010011 |
3 | 112021110101212201222102201 |
4 | 322223020120102212103 |
5 | 1012030110012300413 |
6 | 12324143310424031 |
7 | 564206511105265 |
oct | 72531030224623 |
9 | 15243355658381 |
10 | 4032041134483 |
11 | 1314a851181aa |
12 | 55152a502017 |
13 | 2332b200abcb |
14 | dd21a8adb35 |
15 | 6ed38dbe9dd |
hex | 3aac8612993 |
4032041134483 has 2 divisors, whose sum is σ = 4032041134484. Its totient is φ = 4032041134482.
The previous prime is 4032041134427. The next prime is 4032041134501. The reversal of 4032041134483 is 3844311402304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4032041134483 - 29 = 4032041133971 is a prime.
It is not a weakly prime, because it can be changed into another prime (4032041134183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016020567241 + 2016020567242.
It is an arithmetic number, because the mean of its divisors is an integer number (2016020567242).
Almost surely, 24032041134483 is an apocalyptic number.
4032041134483 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032041134483 is an equidigital number, since it uses as much as digits as its factorization.
4032041134483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 37.
Adding to 4032041134483 its reverse (3844311402304), we get a palindrome (7876352536787).
The spelling of 4032041134483 in words is "four trillion, thirty-two billion, forty-one million, one hundred thirty-four thousand, four hundred eighty-three".
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