Base | Representation |
---|---|
bin | 111010101011001000011… |
… | …100110111001110111001 |
3 | 112021110101221222212122102 |
4 | 322223020130313032321 |
5 | 1012030110314124423 |
6 | 12324143352233145 |
7 | 564206524226654 |
oct | 72531034671671 |
9 | 15243357885572 |
10 | 4032042333113 |
11 | 1314a85866803 |
12 | 55152a99b7b5 |
13 | 2332b233a662 |
14 | dd21ab0289b |
15 | 6ed39059c28 |
hex | 3aac87373b9 |
4032042333113 has 2 divisors, whose sum is σ = 4032042333114. Its totient is φ = 4032042333112.
The previous prime is 4032042333097. The next prime is 4032042333127. The reversal of 4032042333113 is 3113332402304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3172559444224 + 859482888889 = 1781168^2 + 927083^2 .
It is a cyclic number.
It is not a de Polignac number, because 4032042333113 - 24 = 4032042333097 is a prime.
It is not a weakly prime, because it can be changed into another prime (4032042333173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016021166556 + 2016021166557.
It is an arithmetic number, because the mean of its divisors is an integer number (2016021166557).
Almost surely, 24032042333113 is an apocalyptic number.
It is an amenable number.
4032042333113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032042333113 is an equidigital number, since it uses as much as digits as its factorization.
4032042333113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4032042333113 its reverse (3113332402304), we get a palindrome (7145374735417).
The spelling of 4032042333113 in words is "four trillion, thirty-two billion, forty-two million, three hundred thirty-three thousand, one hundred thirteen".
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