Base | Representation |
---|---|
bin | 111010101011001110011… |
… | …001100011101011111001 |
3 | 112021110122220210002010012 |
4 | 322223032121203223321 |
5 | 1012030311341124123 |
6 | 12324201315231305 |
7 | 564212145414512 |
oct | 72531631435371 |
9 | 15243586702105 |
10 | 4032142129913 |
11 | 13150271295a7 |
12 | 5515582a8535 |
13 | 2332c9c0c811 |
14 | dd22a07da09 |
15 | 6ed42bbe378 |
hex | 3aace663af9 |
4032142129913 has 2 divisors, whose sum is σ = 4032142129914. Its totient is φ = 4032142129912.
The previous prime is 4032142129889. The next prime is 4032142130119. The reversal of 4032142129913 is 3199212412304.
4032142129913 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3989958310144 + 42183819769 = 1997488^2 + 205387^2 .
It is a cyclic number.
It is not a de Polignac number, because 4032142129913 - 238 = 3757264222969 is a prime.
It is not a weakly prime, because it can be changed into another prime (4032142129513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016071064956 + 2016071064957.
It is an arithmetic number, because the mean of its divisors is an integer number (2016071064957).
Almost surely, 24032142129913 is an apocalyptic number.
It is an amenable number.
4032142129913 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032142129913 is an equidigital number, since it uses as much as digits as its factorization.
4032142129913 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 4032142129913 in words is "four trillion, thirty-two billion, one hundred forty-two million, one hundred twenty-nine thousand, nine hundred thirteen".
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