4033113121 has 2 divisors, whose sum is σ = 4033113122. Its totient is φ = 4033113120.

The previous prime is 4033113047. The next prime is 4033113127. The reversal of 4033113121 is 1213113304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3043066896 + 990046225 = 55164^2 + 31465^2 .

It is a cyclic number.

It is not a de Polignac number, because 4033113121 - 2⁹ = 4033112609 is a prime.

It is not a weakly prime, because it can be changed into another prime (4033113127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016556560 + 2016556561.

It is an arithmetic number, because the mean of its divisors is an integer number (2016556561).

Almost surely, 2^4033113121 is an apocalyptic number.

It is an amenable number.

4033113121 is a deficient number, since it is larger than the sum of its proper divisors (1).

4033113121 is an equidigital number, since it uses as much as digits as its factorization.

4033113121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 4033113121 is about 63506.7958646947. The cubic root of 4033113121 is about 1591.7693370147.

Adding to 4033113121 its reverse (1213113304), we get a palindrome (5246226425).

The spelling of 4033113121 in words is "four billion, thirty-three million, one hundred thirteen thousand, one hundred twenty-one".