Base | Representation |
---|---|
bin | 100101100011111111… |
… | …100100101100101001 |
3 | 10212002211100220120111 |
4 | 211203333210230221 |
5 | 1130100033043213 |
6 | 30310045254321 |
7 | 2625321011314 |
oct | 454377445451 |
9 | 125084326514 |
10 | 40332315433 |
11 | 161175a45a3 |
12 | 79972643a1 |
13 | 3a59b86207 |
14 | 1d4879397b |
15 | 10b0c7aa3d |
hex | 963fe4b29 |
40332315433 has 2 divisors, whose sum is σ = 40332315434. Its totient is φ = 40332315432.
The previous prime is 40332315427. The next prime is 40332315503. The reversal of 40332315433 is 33451323304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34137366169 + 6194949264 = 184763^2 + 78708^2 .
It is a cyclic number.
It is not a de Polignac number, because 40332315433 - 213 = 40332307241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40332315395 and 40332315404.
It is not a weakly prime, because it can be changed into another prime (40336315433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20166157716 + 20166157717.
It is an arithmetic number, because the mean of its divisors is an integer number (20166157717).
Almost surely, 240332315433 is an apocalyptic number.
It is an amenable number.
40332315433 is a deficient number, since it is larger than the sum of its proper divisors (1).
40332315433 is an equidigital number, since it uses as much as digits as its factorization.
40332315433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 31.
Adding to 40332315433 its reverse (33451323304), we get a palindrome (73783638737).
The spelling of 40332315433 in words is "forty billion, three hundred thirty-two million, three hundred fifteen thousand, four hundred thirty-three".
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