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40334012141 = 53761019097
BaseRepresentation
bin100101100100000110…
…000010111011101101
310212002221120010000112
4211210012002323231
51130101001342031
630310145505405
72625341306063
oct454406027355
9125087503015
1040334012141
1116118553335
127997942265
133a5a32b597
141d48ab6033
1510b0eb362b
hex964182eed

40334012141 has 4 divisors (see below), whose sum is σ = 41095031292. Its totient is φ = 39572992992.

The previous prime is 40334012119. The next prime is 40334012149. The reversal of 40334012141 is 14121043304.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9649132900 + 30684879241 = 98230^2 + 175171^2 .

It is a cyclic number.

It is not a de Polignac number, because 40334012141 - 230 = 39260270317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40334012149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380509496 + ... + 380509601.

It is an arithmetic number, because the mean of its divisors is an integer number (10273757823).

Almost surely, 240334012141 is an apocalyptic number.

It is an amenable number.

40334012141 is a deficient number, since it is larger than the sum of its proper divisors (761019151).

40334012141 is an equidigital number, since it uses as much as digits as its factorization.

40334012141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 761019150.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 40334012141 its reverse (14121043304), we get a palindrome (54455055445).

The spelling of 40334012141 in words is "forty billion, three hundred thirty-four million, twelve thousand, one hundred forty-one".

Divisors: 1 53 761019097 40334012141