Base | Representation |
---|---|
bin | 111010101101001010010… |
… | …000011111111111100001 |
3 | 112021200000201220102201111 |
4 | 322231022100133333201 |
5 | 1012044040323132043 |
6 | 12325143430103321 |
7 | 564314510213554 |
oct | 72551220377741 |
9 | 15250021812644 |
10 | 4034220130273 |
11 | 13159a3100a73 |
12 | 551a381aab41 |
13 | 23356b597028 |
14 | dd38604069b |
15 | 6ee1533d09d |
hex | 3ab4a41ffe1 |
4034220130273 has 2 divisors, whose sum is σ = 4034220130274. Its totient is φ = 4034220130272.
The previous prime is 4034220130247. The next prime is 4034220130277. The reversal of 4034220130273 is 3720310224304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3283862252449 + 750357877824 = 1812143^2 + 866232^2 .
It is a cyclic number.
It is not a de Polignac number, because 4034220130273 - 221 = 4034218033121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4034220130277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017110065136 + 2017110065137.
It is an arithmetic number, because the mean of its divisors is an integer number (2017110065137).
Almost surely, 24034220130273 is an apocalyptic number.
It is an amenable number.
4034220130273 is a deficient number, since it is larger than the sum of its proper divisors (1).
4034220130273 is an equidigital number, since it uses as much as digits as its factorization.
4034220130273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 31.
Adding to 4034220130273 its reverse (3720310224304), we get a palindrome (7754530354577).
The spelling of 4034220130273 in words is "four trillion, thirty-four billion, two hundred twenty million, one hundred thirty thousand, two hundred seventy-three".
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