4034315121 has 4 divisors (see below), whose sum is σ = 5379086832. Its totient is φ = 2689543412.

The previous prime is 4034315119. The next prime is 4034315123. The reversal of 4034315121 is 1215134304.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (4034315119) and next prime (4034315123).

It is a cyclic number.

It is not a de Polignac number, because 4034315121 - 2¹ = 4034315119 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4034315091 and 4034315100.

It is not an unprimeable number, because it can be changed into a prime (4034315123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 672385851 + ... + 672385856.

It is an arithmetic number, because the mean of its divisors is an integer number (1344771708).

Almost surely, 2^4034315121 is an apocalyptic number.

It is an amenable number.

4034315121 is a deficient number, since it is larger than the sum of its proper divisors (1344771711).

4034315121 is a wasteful number, since it uses less digits than its factorization.

4034315121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1344771710.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 4034315121 is about 63516.2587138128. The cubic root of 4034315121 is about 1591.9274544657.

Adding to 4034315121 its reverse (1215134304), we get a palindrome (5249449425).

The spelling of 4034315121 in words is "four billion, thirty-four million, three hundred fifteen thousand, one hundred twenty-one".