Base | Representation |
---|---|
bin | 10010010110010111101001… |
… | …00010110011000001111001 |
3 | 12021212112001100102002210101 |
4 | 21023023310202303001321 |
5 | 20242102400014304431 |
6 | 221453001043515401 |
7 | 11333160012651112 |
oct | 1113136442630171 |
9 | 167775040362711 |
10 | 40351025541241 |
11 | 11947856a72768 |
12 | 4638370988b61 |
13 | 196911577690c |
14 | 9d7000227209 |
15 | 49e951ce9961 |
hex | 24b2f48b3079 |
40351025541241 has 2 divisors, whose sum is σ = 40351025541242. Its totient is φ = 40351025541240.
The previous prime is 40351025541221. The next prime is 40351025541283. The reversal of 40351025541241 is 14214552015304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38728268025616 + 1622757515625 = 6223204^2 + 1273875^2 .
It is a cyclic number.
It is not a de Polignac number, because 40351025541241 - 215 = 40351025508473 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40351025541241.
It is not a weakly prime, because it can be changed into another prime (40351025541221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20175512770620 + 20175512770621.
It is an arithmetic number, because the mean of its divisors is an integer number (20175512770621).
Almost surely, 240351025541241 is an apocalyptic number.
It is an amenable number.
40351025541241 is a deficient number, since it is larger than the sum of its proper divisors (1).
40351025541241 is an equidigital number, since it uses as much as digits as its factorization.
40351025541241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 37.
Adding to 40351025541241 its reverse (14214552015304), we get a palindrome (54565577556545).
The spelling of 40351025541241 in words is "forty trillion, three hundred fifty-one billion, twenty-five million, five hundred forty-one thousand, two hundred forty-one".
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