Base | Representation |
---|---|
bin | 100101100101001001… |
… | …100100001000110001 |
3 | 10212011011212100101012 |
4 | 211211021210020301 |
5 | 1130120014234133 |
6 | 30312021120305 |
7 | 2625644614421 |
oct | 454511441061 |
9 | 125134770335 |
10 | 40351711793 |
11 | 16127542348 |
12 | 79a1859095 |
13 | 3a60bb7953 |
14 | 1d4b1a2481 |
15 | 10b280cb48 |
hex | 965264231 |
40351711793 has 2 divisors, whose sum is σ = 40351711794. Its totient is φ = 40351711792.
The previous prime is 40351711759. The next prime is 40351711901. The reversal of 40351711793 is 39711715304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 37028535184 + 3323176609 = 192428^2 + 57647^2 .
It is a cyclic number.
It is not a de Polignac number, because 40351711793 - 214 = 40351695409 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 40351711793.
It is not a weakly prime, because it can be changed into another prime (40351711723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20175855896 + 20175855897.
It is an arithmetic number, because the mean of its divisors is an integer number (20175855897).
Almost surely, 240351711793 is an apocalyptic number.
It is an amenable number.
40351711793 is a deficient number, since it is larger than the sum of its proper divisors (1).
40351711793 is an equidigital number, since it uses as much as digits as its factorization.
40351711793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 79380, while the sum is 41.
The spelling of 40351711793 in words is "forty billion, three hundred fifty-one million, seven hundred eleven thousand, seven hundred ninety-three".
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