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40354217713 is a prime number
BaseRepresentation
bin100101100101010011…
…000111111011110001
310212011100120122212001
4211211103013323301
51130121134431323
630312150534001
72626005122335
oct454523077361
9125140518761
1040354217713
11161289a4057
1279a2667301
133a61584444
141d4b6557c5
1510b2b553ad
hex9654c7ef1

40354217713 has 2 divisors, whose sum is σ = 40354217714. Its totient is φ = 40354217712.

The previous prime is 40354217689. The next prime is 40354217731. The reversal of 40354217713 is 31771245304.

Together with next prime (40354217731) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32742178704 + 7612039009 = 180948^2 + 87247^2 .

It is a cyclic number.

It is not a de Polignac number, because 40354217713 - 25 = 40354217681 is a prime.

It is not a weakly prime, because it can be changed into another prime (40354217773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20177108856 + 20177108857.

It is an arithmetic number, because the mean of its divisors is an integer number (20177108857).

Almost surely, 240354217713 is an apocalyptic number.

It is an amenable number.

40354217713 is a deficient number, since it is larger than the sum of its proper divisors (1).

40354217713 is an equidigital number, since it uses as much as digits as its factorization.

40354217713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70560, while the sum is 37.

The spelling of 40354217713 in words is "forty billion, three hundred fifty-four million, two hundred seventeen thousand, seven hundred thirteen".