Base | Representation |
---|---|
bin | 10010010111001000100101… |
… | …11001001010100101011011 |
3 | 12021222000212202221210200121 |
4 | 21023210102321022211123 |
5 | 20243020204424301042 |
6 | 221513024433414111 |
7 | 11335110150432412 |
oct | 1113442271124533 |
9 | 167860782853617 |
10 | 40377304525147 |
11 | 11957a11852287 |
12 | 464148570a337 |
13 | 196b742c6a335 |
14 | 9d83b43c0479 |
15 | 4a048de0a367 |
hex | 24b912e4a95b |
40377304525147 has 2 divisors, whose sum is σ = 40377304525148. Its totient is φ = 40377304525146.
The previous prime is 40377304525013. The next prime is 40377304525247. The reversal of 40377304525147 is 74152540377304.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-40377304525147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 40377304525094 and 40377304525103.
It is not a weakly prime, because it can be changed into another prime (40377304525247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20188652262573 + 20188652262574.
It is an arithmetic number, because the mean of its divisors is an integer number (20188652262574).
Almost surely, 240377304525147 is an apocalyptic number.
40377304525147 is a deficient number, since it is larger than the sum of its proper divisors (1).
40377304525147 is an equidigital number, since it uses as much as digits as its factorization.
40377304525147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9878400, while the sum is 52.
The spelling of 40377304525147 in words is "forty trillion, three hundred seventy-seven billion, three hundred four million, five hundred twenty-five thousand, one hundred forty-seven".
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