Base | Representation |
---|---|
bin | 111010110010100100000… |
… | …001111000000011110111 |
3 | 112022020000000122222210021 |
4 | 322302210001320003313 |
5 | 1012142430412312211 |
6 | 12331543215310011 |
7 | 564611330465500 |
oct | 72624401700367 |
9 | 15266000588707 |
10 | 4040021213431 |
11 | 13183aa719675 |
12 | 552b96b1b307 |
13 | 233c84397808 |
14 | dd77666dba7 |
15 | 70154782771 |
hex | 3aca40780f7 |
4040021213431 has 12 divisors (see below), whose sum is σ = 4727757939408. Its totient is φ = 3442139538432.
The previous prime is 4040021213413. The next prime is 4040021213443. The reversal of 4040021213431 is 1343121200404.
It is not a de Polignac number, because 4040021213431 - 29 = 4040021212919 is a prime.
It is a super-2 number, since 2×40400212134312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4040021213396 and 4040021213405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4040021213411) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 246846346 + ... + 246862711.
It is an arithmetic number, because the mean of its divisors is an integer number (393979828284).
Almost surely, 24040021213431 is an apocalyptic number.
4040021213431 is a deficient number, since it is larger than the sum of its proper divisors (687736725977).
4040021213431 is a wasteful number, since it uses less digits than its factorization.
4040021213431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 493709238 (or 493709231 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4040021213431 its reverse (1343121200404), we get a palindrome (5383142413835).
The spelling of 4040021213431 in words is "four trillion, forty billion, twenty-one million, two hundred thirteen thousand, four hundred thirty-one".
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