404010413 has 4 divisors (see below), whose sum is σ = 413406048. Its totient is φ = 394614780.

The previous prime is 404010401. The next prime is 404010421. The reversal of 404010413 is 314010404.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 404010413 - 2¹⁴ = 403994029 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 404010391 and 404010400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (404010473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4697753 + ... + 4697838.

It is an arithmetic number, because the mean of its divisors is an integer number (103351512).

Almost surely, 2^404010413 is an apocalyptic number.

404010413 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

404010413 is a deficient number, since it is larger than the sum of its proper divisors (9395635).

404010413 is an equidigital number, since it uses as much as digits as its factorization.

404010413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9395634.

The product of its (nonzero) digits is 192, while the sum is 17.

The square root of 404010413 is about 20100.0102736292. The cubic root of 404010413 is about 739.2605304813.

Adding to 404010413 its reverse (314010404), we get a palindrome (718020817).

Subtracting from 404010413 its reverse (314010404), we obtain a palindrome (90000009).

The spelling of 404010413 in words is "four hundred four million, ten thousand, four hundred thirteen".