Base | Representation |
---|---|
bin | 11000001110001100… |
… | …11000000001000000 |
3 | 1020120021100100010112 |
4 | 30013012120001000 |
5 | 203113011414012 |
6 | 5550213050452 |
7 | 640152202121 |
oct | 140706300100 |
9 | 36507310115 |
10 | 13004013632 |
11 | 5573476a05 |
12 | 262b026a28 |
13 | 12c317882c |
14 | 8b50d2048 |
15 | 511996122 |
hex | 307198040 |
13004013632 has 28 divisors (see below), whose sum is σ = 25821160956. Its totient is φ = 6497894400.
The previous prime is 13004013601. The next prime is 13004013667. The reversal of 13004013632 is 23631040031.
It can be written as a sum of positive squares in 2 ways, for example, as 12673355776 + 330657856 = 112576^2 + 18184^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13004013598 and 13004013607.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39008 + ... + 165920.
Almost surely, 213004013632 is an apocalyptic number.
It is an amenable number.
13004013632 is a deficient number, since it is larger than the sum of its proper divisors (12817147324).
13004013632 is a wasteful number, since it uses less digits than its factorization.
13004013632 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 128526 (or 128516 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13004013632 its reverse (23631040031), we get a palindrome (36635053663).
The spelling of 13004013632 in words is "thirteen billion, four million, thirteen thousand, six hundred thirty-two".
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