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404011002241313 is a prime number
BaseRepresentation
bin101101111011100100010010…
…0010001100010000100100001
31221222111002000101121120210222
41123313020210101202010201
5410423304013033210223
63551132031525132425
7151045555156304645
oct13367104421420441
91858432011546728
10404011002241313
11107804116246a85
123939005725a115
13144580c687703c
1471aa345c7cc25
1531a93bee6c0c8
hex16f7224462121

404011002241313 has 2 divisors, whose sum is σ = 404011002241314. Its totient is φ = 404011002241312.

The previous prime is 404011002241307. The next prime is 404011002241403. The reversal of 404011002241313 is 313142200110404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 390462065772769 + 13548936468544 = 19760113^2 + 3680888^2 .

It is a cyclic number.

It is not a de Polignac number, because 404011002241313 - 238 = 403736124334369 is a prime.

It is not a weakly prime, because it can be changed into another prime (404011092241313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202005501120656 + 202005501120657.

It is an arithmetic number, because the mean of its divisors is an integer number (202005501120657).

Almost surely, 2404011002241313 is an apocalyptic number.

It is an amenable number.

404011002241313 is a deficient number, since it is larger than the sum of its proper divisors (1).

404011002241313 is an equidigital number, since it uses as much as digits as its factorization.

404011002241313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 404011002241313 its reverse (313142200110404), we get a palindrome (717153202351717).

The spelling of 404011002241313 in words is "four hundred four trillion, eleven billion, two million, two hundred forty-one thousand, three hundred thirteen".