Search a number
-
+
4040111953 is a prime number
BaseRepresentation
bin1111000011001111…
…0011011101010001
3101102120011221201001
43300303303131101
531233232040303
61504521342001
7202055246023
oct36063633521
911376157631
104040111953
1117935a09a9
12949037901
134c50271b7
142a47d6013
15189a4a31d
hexf0cf3751

4040111953 has 2 divisors, whose sum is σ = 4040111954. Its totient is φ = 4040111952.

The previous prime is 4040111947. The next prime is 4040112001. The reversal of 4040111953 is 3591110404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2706912784 + 1333199169 = 52028^2 + 36513^2 .

It is a cyclic number.

It is not a de Polignac number, because 4040111953 - 213 = 4040103761 is a prime.

It is a super-4 number, since 4×40401119534 (a number of 40 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (4040151953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020055976 + 2020055977.

It is an arithmetic number, because the mean of its divisors is an integer number (2020055977).

Almost surely, 24040111953 is an apocalyptic number.

It is an amenable number.

4040111953 is a deficient number, since it is larger than the sum of its proper divisors (1).

4040111953 is an equidigital number, since it uses as much as digits as its factorization.

4040111953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

The square root of 4040111953 is about 63561.8749959439. The cubic root of 4040111953 is about 1592.6895598331.

The spelling of 4040111953 in words is "four billion, forty million, one hundred eleven thousand, nine hundred fifty-three".