4040130001 has 2 divisors, whose sum is σ = 4040130002. Its totient is φ = 4040130000.

The previous prime is 4040129959. The next prime is 4040130007. The reversal of 4040130001 is 1000310404.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3786556225 + 253573776 = 61535^2 + 15924^2 .

It is a cyclic number.

It is not a de Polignac number, because 4040130001 - 2¹³ = 4040121809 is a prime.

It is a super-3 number, since 3×4040130001³ (a number of 30 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4040130007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020065000 + 2020065001.

It is an arithmetic number, because the mean of its divisors is an integer number (2020065001).

Almost surely, 2^4040130001 is an apocalyptic number.

It is an amenable number.

4040130001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4040130001 is an equidigital number, since it uses as much as digits as its factorization.

4040130001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 4040130001 is about 63562.0169676828. The cubic root of 4040130001 is about 1592.6919314521.

Adding to 4040130001 its reverse (1000310404), we get a palindrome (5040440405).

The spelling of 4040130001 in words is "four billion, forty million, one hundred thirty thousand, one".