Base | Representation |
---|---|
bin | 100101101000000110… |
… | …101110101101101111 |
3 | 10212021122011201001212 |
4 | 211220012232231233 |
5 | 1130220213102320 |
6 | 30320552025035 |
7 | 2630116246424 |
oct | 455006565557 |
9 | 125248151055 |
10 | 40401300335 |
11 | 16152531a10 |
12 | 79b639217b |
13 | 3a6b25a996 |
14 | 1d539cdd4b |
15 | 10b6d559c5 |
hex | 9681aeb6f |
40401300335 has 32 divisors (see below), whose sum is σ = 53594956800. Its totient is φ = 28991064960.
The previous prime is 40401300299. The next prime is 40401300353. The reversal of 40401300335 is 53300310404.
It is not a de Polignac number, because 40401300335 - 212 = 40401296239 is a prime.
It is a super-2 number, since 2×404013003352 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40401300335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10030592 + ... + 10034618.
It is an arithmetic number, because the mean of its divisors is an integer number (1674842400).
Almost surely, 240401300335 is an apocalyptic number.
40401300335 is a deficient number, since it is larger than the sum of its proper divisors (13193656465).
40401300335 is a wasteful number, since it uses less digits than its factorization.
40401300335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6431.
The product of its (nonzero) digits is 2160, while the sum is 23.
Adding to 40401300335 its reverse (53300310404), we get a palindrome (93701610739).
The spelling of 40401300335 in words is "forty billion, four hundred one million, three hundred thousand, three hundred thirty-five".
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