Search a number
-
+
4040151389123 is a prime number
BaseRepresentation
bin111010110010101011110…
…010011101001111000011
3112022020100002121121021012
4322302223302131033003
51012143212223422443
612332004145351135
7564614501120453
oct72625362351703
915266302547235
104040151389123
111318467150593
125530126384ab
13233ca5345255
14dd789a77d63
1570160de8118
hex3acabc9d3c3

4040151389123 has 2 divisors, whose sum is σ = 4040151389124. Its totient is φ = 4040151389122.

The previous prime is 4040151389093. The next prime is 4040151389149. The reversal of 4040151389123 is 3219831510404.

4040151389123 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4040151389123 - 26 = 4040151389059 is a prime.

It is a super-4 number, since 4×40401513891234 (a number of 52 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (4040151380123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020075694561 + 2020075694562.

It is an arithmetic number, because the mean of its divisors is an integer number (2020075694562).

Almost surely, 24040151389123 is an apocalyptic number.

4040151389123 is a deficient number, since it is larger than the sum of its proper divisors (1).

4040151389123 is an equidigital number, since it uses as much as digits as its factorization.

4040151389123 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 41.

Adding to 4040151389123 its reverse (3219831510404), we get a palindrome (7259982899527).

The spelling of 4040151389123 in words is "four trillion, forty billion, one hundred fifty-one million, three hundred eighty-nine thousand, one hundred twenty-three".