Base | Representation |
---|---|
bin | 10010010111111001001101… |
… | …10010011110000010001011 |
3 | 12022001112020222110201011011 |
4 | 21023330212302132002023 |
5 | 20243432134434233044 |
6 | 221533023000144351 |
7 | 11340023055342361 |
oct | 1113744662360213 |
9 | 168045228421134 |
10 | 40403408117899 |
11 | 11967a97627932 |
12 | 464654b7680b7 |
13 | 19710430118c8 |
14 | 9d976d15d631 |
15 | 4a0eba923134 |
hex | 24bf26c9e08b |
40403408117899 has 2 divisors, whose sum is σ = 40403408117900. Its totient is φ = 40403408117898.
The previous prime is 40403408117867. The next prime is 40403408117921. The reversal of 40403408117899 is 99871180430404.
40403408117899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40403408117899 - 25 = 40403408117867 is a prime.
It is not a weakly prime, because it can be changed into another prime (40403408117099) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20201704058949 + 20201704058950.
It is an arithmetic number, because the mean of its divisors is an integer number (20201704058950).
Almost surely, 240403408117899 is an apocalyptic number.
40403408117899 is a deficient number, since it is larger than the sum of its proper divisors (1).
40403408117899 is an equidigital number, since it uses as much as digits as its factorization.
40403408117899 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6967296, while the sum is 58.
The spelling of 40403408117899 in words is "forty trillion, four hundred three billion, four hundred eight million, one hundred seventeen thousand, eight hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •