Search a number
-
+
404042113 is a prime number
BaseRepresentation
bin11000000101010…
…011000110000001
31001011021110120201
4120011103012001
51311413321423
6104032005201
713004205226
oct3005230601
91034243521
10404042113
11198086902
12b3390801
1365928397
143b93794d
15257112ad
hex18153181

404042113 has 2 divisors, whose sum is σ = 404042114. Its totient is φ = 404042112.

The previous prime is 404042071. The next prime is 404042131. The reversal of 404042113 is 311240404.

Together with next prime (404042131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 338302449 + 65739664 = 18393^2 + 8108^2 .

It is a cyclic number.

It is not a de Polignac number, because 404042113 - 213 = 404033921 is a prime.

It is not a weakly prime, because it can be changed into another prime (404042153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202021056 + 202021057.

It is an arithmetic number, because the mean of its divisors is an integer number (202021057).

Almost surely, 2404042113 is an apocalyptic number.

It is an amenable number.

404042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

404042113 is an equidigital number, since it uses as much as digits as its factorization.

404042113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 19.

The square root of 404042113 is about 20100.7988149725. The cubic root of 404042113 is about 739.2798649218.

Adding to 404042113 its reverse (311240404), we get a palindrome (715282517).

The spelling of 404042113 in words is "four hundred four million, forty-two thousand, one hundred thirteen".