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40411410131 is a prime number
BaseRepresentation
bin100101101000101101…
…010010111011010011
310212022100012100002202
4211220231102323103
51130230310111011
630321552433415
72630301214151
oct455055227323
9125270170082
1040411410131
1116158207614
1279b984886b
133a7038a501
141d550a23d1
1510b7ba123b
hex968b52ed3

40411410131 has 2 divisors, whose sum is σ = 40411410132. Its totient is φ = 40411410130.

The previous prime is 40411410049. The next prime is 40411410163. The reversal of 40411410131 is 13101411404.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40411410131 - 210 = 40411409107 is a prime.

It is a super-2 number, since 2×404114101312 (a number of 22 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (40411410031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20205705065 + 20205705066.

It is an arithmetic number, because the mean of its divisors is an integer number (20205705066).

Almost surely, 240411410131 is an apocalyptic number.

40411410131 is a deficient number, since it is larger than the sum of its proper divisors (1).

40411410131 is an equidigital number, since it uses as much as digits as its factorization.

40411410131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 40411410131 its reverse (13101411404), we get a palindrome (53512821535).

The spelling of 40411410131 in words is "forty billion, four hundred eleven million, four hundred ten thousand, one hundred thirty-one".