Base | Representation |
---|---|
bin | 111010110100100001111… |
… | …101100110010010111011 |
3 | 112022102110021021202022211 |
4 | 322310201331212102323 |
5 | 1012211242302140212 |
6 | 12332533012155551 |
7 | 565014564165304 |
oct | 72644175462273 |
9 | 15272407252284 |
10 | 4042134021307 |
11 | 1319294305488 |
12 | 553486608bb7 |
13 | 23423001b2a5 |
14 | dd8d70d17ab |
15 | 70229ec99a7 |
hex | 3ad21f664bb |
4042134021307 has 2 divisors, whose sum is σ = 4042134021308. Its totient is φ = 4042134021306.
The previous prime is 4042134021221. The next prime is 4042134021361. The reversal of 4042134021307 is 7031204312404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4042134021307 - 239 = 3492378207419 is a prime.
It is a super-3 number, since 3×40421340213073 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4042134021407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021067010653 + 2021067010654.
It is an arithmetic number, because the mean of its divisors is an integer number (2021067010654).
Almost surely, 24042134021307 is an apocalyptic number.
4042134021307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042134021307 is an equidigital number, since it uses as much as digits as its factorization.
4042134021307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 4042134021307 in words is "four trillion, forty-two billion, one hundred thirty-four million, twenty-one thousand, three hundred seven".
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