Search a number
-
+
4042202023131 = 37197911938257
BaseRepresentation
bin111010110100100110000…
…001000000010011011011
3112022102122000020121021220
4322310212001000103123
51012211412204220011
612332543441503123
7565016351200326
oct72644601002333
915272560217256
104042202023131
111319319731238
125534a5341aa3
1323424113a45c
14dd9021537bd
1570230e5d506
hex3ad260404db

4042202023131 has 16 divisors (see below), whose sum is σ = 5466073632768. Its totient is φ = 2656573673600.

The previous prime is 4042202023129. The next prime is 4042202023147. The reversal of 4042202023131 is 1313202022404.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 4042202023131 - 21 = 4042202023129 is a prime.

It is a super-2 number, since 2×40422020231312 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (4042202023031) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1116355 + ... + 3054611.

It is an arithmetic number, because the mean of its divisors is an integer number (341629602048).

Almost surely, 24042202023131 is an apocalyptic number.

4042202023131 is a deficient number, since it is larger than the sum of its proper divisors (1423871609637).

4042202023131 is a wasteful number, since it uses less digits than its factorization.

4042202023131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1948122.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 4042202023131 its reverse (1313202022404), we get a palindrome (5355404045535).

The spelling of 4042202023131 in words is "four trillion, forty-two billion, two hundred two million, twenty-three thousand, one hundred thirty-one".

Divisors: 1 3 71 213 9791 29373 695161 1938257 2085483 5814771 137616247 412848741 18977474287 56932422861 1347400674377 4042202023131