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4042511491 is a prime number
BaseRepresentation
bin1111000011110011…
…1101010010000011
3101102201200212020211
43300330331102003
531234340331431
61505045014551
7202114531534
oct36074752203
911381625224
104042511491
11179498a797
129499b4457
134c5687445
142a4c5c68b
15189d712b1
hexf0f3d483

4042511491 has 2 divisors, whose sum is σ = 4042511492. Its totient is φ = 4042511490.

The previous prime is 4042511423. The next prime is 4042511513. The reversal of 4042511491 is 1941152404.

4042511491 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4042511491 is a prime.

It is not a weakly prime, because it can be changed into another prime (4042511191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021255745 + 2021255746.

It is an arithmetic number, because the mean of its divisors is an integer number (2021255746).

Almost surely, 24042511491 is an apocalyptic number.

4042511491 is a deficient number, since it is larger than the sum of its proper divisors (1).

4042511491 is an equidigital number, since it uses as much as digits as its factorization.

4042511491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

The square root of 4042511491 is about 63580.7478015161. The cubic root of 4042511491 is about 1593.0048120510.

Adding to 4042511491 its reverse (1941152404), we get a palindrome (5983663895).

The spelling of 4042511491 in words is "four billion, forty-two million, five hundred eleven thousand, four hundred ninety-one".