Base | Representation |
---|---|
bin | 10010011000101011100000… |
… | …10110111001111111010011 |
3 | 12022011002221221102201200022 |
4 | 21030111300112321333103 |
5 | 20244402441011211011 |
6 | 221553250331414055 |
7 | 11342000206341266 |
oct | 1114256026717723 |
9 | 168132857381608 |
10 | 40430412210131 |
11 | 11978494746029 |
12 | 464b8272b432b |
13 | 19737577c5cc8 |
14 | 9dabb1748cdd |
15 | 4a1a4b5158db |
hex | 24c5705b9fd3 |
40430412210131 has 2 divisors, whose sum is σ = 40430412210132. Its totient is φ = 40430412210130.
The previous prime is 40430412210079. The next prime is 40430412210143. The reversal of 40430412210131 is 13101221403404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40430412210131 - 214 = 40430412193747 is a prime.
It is a super-2 number, since 2×404304122101312 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 40430412210131.
It is not a weakly prime, because it can be changed into another prime (40430412210431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20215206105065 + 20215206105066.
It is an arithmetic number, because the mean of its divisors is an integer number (20215206105066).
Almost surely, 240430412210131 is an apocalyptic number.
40430412210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
40430412210131 is an equidigital number, since it uses as much as digits as its factorization.
40430412210131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 40430412210131 its reverse (13101221403404), we get a palindrome (53531633613535).
The spelling of 40430412210131 in words is "forty trillion, four hundred thirty billion, four hundred twelve million, two hundred ten thousand, one hundred thirty-one".
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