Base | Representation |
---|---|
bin | 111010110101011011101… |
… | …011011010010110101011 |
3 | 112022111221202100001100002 |
4 | 322311123223122112223 |
5 | 1012220233144113311 |
6 | 12333213042333215 |
7 | 565050562534436 |
oct | 72653353322653 |
9 | 15274852301302 |
10 | 4043102332331 |
11 | 1319740954927 |
12 | 5536b695a20b |
13 | 2343558117aa |
14 | dd98995081d |
15 | 70284eeb93b |
hex | 3ad5bada5ab |
4043102332331 has 2 divisors, whose sum is σ = 4043102332332. Its totient is φ = 4043102332330.
The previous prime is 4043102332327. The next prime is 4043102332387. The reversal of 4043102332331 is 1332332013404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4043102332331 - 22 = 4043102332327 is a prime.
It is a super-2 number, since 2×40431023323312 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 4043102332294 and 4043102332303.
It is not a weakly prime, because it can be changed into another prime (4043102335331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021551166165 + 2021551166166.
It is an arithmetic number, because the mean of its divisors is an integer number (2021551166166).
Almost surely, 24043102332331 is an apocalyptic number.
4043102332331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043102332331 is an equidigital number, since it uses as much as digits as its factorization.
4043102332331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4043102332331 its reverse (1332332013404), we get a palindrome (5375434345735).
The spelling of 4043102332331 in words is "four trillion, forty-three billion, one hundred two million, three hundred thirty-two thousand, three hundred thirty-one".
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