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40431113 is a prime number
BaseRepresentation
bin1001101000111…
…0111000001001
32211002010001122
42122032320021
540322243423
64002325025
71000441652
oct232167011
984063048
1040431113
1120905548
1211659775
1384b7b48
145526529
1538398c8
hex268ee09

40431113 has 2 divisors, whose sum is σ = 40431114. Its totient is φ = 40431112.

The previous prime is 40431109. The next prime is 40431119. The reversal of 40431113 is 31113404.

40431113 is nontrivially palindromic in base 13.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39778249 + 652864 = 6307^2 + 808^2 .

It is a cyclic number.

It is not a de Polignac number, because 40431113 - 22 = 40431109 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 40431091 and 40431100.

It is not a weakly prime, because it can be changed into another prime (40431119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20215556 + 20215557.

It is an arithmetic number, because the mean of its divisors is an integer number (20215557).

Almost surely, 240431113 is an apocalyptic number.

It is an amenable number.

40431113 is a deficient number, since it is larger than the sum of its proper divisors (1).

40431113 is an equidigital number, since it uses as much as digits as its factorization.

40431113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 40431113 is about 6358.5464533964. The cubic root of 40431113 is about 343.2194562688.

Adding to 40431113 its reverse (31113404), we get a palindrome (71544517).

The spelling of 40431113 in words is "forty million, four hundred thirty-one thousand, one hundred thirteen".