Base | Representation |
---|---|
bin | 101101111101110000001011… |
… | …0101100010111001001101011 |
3 | 1222000112210110011120212010022 |
4 | 1123323200112230113021223 |
5 | 410443214243024313141 |
6 | 3551522034141311055 |
7 | 151106351643100301 |
oct | 13373402654271153 |
9 | 1860483404525108 |
10 | 404311422104171 |
11 | 10790a56944547a |
12 | 3941a31926548b |
13 | 1447a5326800ba |
14 | 71baac4a76271 |
15 | 31b2104414b4b |
hex | 16fb816b1726b |
404311422104171 has 2 divisors, whose sum is σ = 404311422104172. Its totient is φ = 404311422104170.
The previous prime is 404311422104167. The next prime is 404311422104231. The reversal of 404311422104171 is 171401224113404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 404311422104171 - 22 = 404311422104167 is a prime.
It is not a weakly prime, because it can be changed into another prime (404311422100171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202155711052085 + 202155711052086.
It is an arithmetic number, because the mean of its divisors is an integer number (202155711052086).
Almost surely, 2404311422104171 is an apocalyptic number.
404311422104171 is a deficient number, since it is larger than the sum of its proper divisors (1).
404311422104171 is an equidigital number, since it uses as much as digits as its factorization.
404311422104171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 404311422104171 its reverse (171401224113404), we get a palindrome (575712646217575).
The spelling of 404311422104171 in words is "four hundred four trillion, three hundred eleven billion, four hundred twenty-two million, one hundred four thousand, one hundred seventy-one".
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