Base | Representation |
---|---|
bin | 111010110101011101011… |
… | …001101100111100011010 |
3 | 112022112000202201221010021 |
4 | 322311131121230330122 |
5 | 1012220313044304224 |
6 | 12333215554141054 |
7 | 565051363352101 |
oct | 72653531547432 |
9 | 15275022657107 |
10 | 4043131244314 |
11 | 1319756201928 |
12 | 55370458178a |
13 | 23435b7c5486 |
14 | dd98d719038 |
15 | 7028780d1e4 |
hex | 3ad5d66cf1a |
4043131244314 has 4 divisors (see below), whose sum is σ = 6064696866474. Its totient is φ = 2021565622156.
The previous prime is 4043131244311. The next prime is 4043131244353. The reversal of 4043131244314 is 4134421313404.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4001420126025 + 41711118289 = 2000355^2 + 204233^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 4043131244314.
It is not an unprimeable number, because it can be changed into a prime (4043131244311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1010782811077 + ... + 1010782811080.
Almost surely, 24043131244314 is an apocalyptic number.
4043131244314 is a deficient number, since it is larger than the sum of its proper divisors (2021565622160).
4043131244314 is a wasteful number, since it uses less digits than its factorization.
4043131244314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2021565622159.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 4043131244314 its reverse (4134421313404), we get a palindrome (8177552557718).
The spelling of 4043131244314 in words is "four trillion, forty-three billion, one hundred thirty-one million, two hundred forty-four thousand, three hundred fourteen".
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