Base | Representation |
---|---|
bin | 111010110101101101101… |
… | …011110000110000110001 |
3 | 112022112201210202101111002 |
4 | 322311231223300300301 |
5 | 1012221343012222001 |
6 | 12333303033131345 |
7 | 565061221304141 |
oct | 72655553606061 |
9 | 15275653671432 |
10 | 4043404414001 |
11 | 13198864202a7 |
12 | 55377bb59b55 |
13 | 2343a328ac44 |
14 | dd9b7b06921 |
15 | 702a17bc46b |
hex | 3ad6daf0c31 |
4043404414001 has 2 divisors, whose sum is σ = 4043404414002. Its totient is φ = 4043404414000.
The previous prime is 4043404413947. The next prime is 4043404414009. The reversal of 4043404414001 is 1004144043404.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2959858739776 + 1083545674225 = 1720424^2 + 1040935^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4043404414001 is a prime.
It is not a weakly prime, because it can be changed into another prime (4043404414009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021702207000 + 2021702207001.
It is an arithmetic number, because the mean of its divisors is an integer number (2021702207001).
Almost surely, 24043404414001 is an apocalyptic number.
It is an amenable number.
4043404414001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043404414001 is an equidigital number, since it uses as much as digits as its factorization.
4043404414001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 29.
Adding to 4043404414001 its reverse (1004144043404), we get a palindrome (5047548457405).
The spelling of 4043404414001 in words is "four trillion, forty-three billion, four hundred four million, four hundred fourteen thousand, one".
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