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4043410313113 is a prime number
BaseRepresentation
bin111010110101101110000…
…010010000111110011001
3112022112202012212002112201
4322311232002100332121
51012221401020004423
612333303403410201
7565061322403543
oct72655602207631
915275665762481
104043410313113
11131988978a3a6
12553781b23961
132343a4575042
14dd9b8800693
15702a20852ad
hex3ad6e090f99

4043410313113 has 2 divisors, whose sum is σ = 4043410313114. Its totient is φ = 4043410313112.

The previous prime is 4043410313077. The next prime is 4043410313171. The reversal of 4043410313113 is 3113130143404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3732283975744 + 311126337369 = 1931912^2 + 557787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4043410313113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4043410310113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021705156556 + 2021705156557.

It is an arithmetic number, because the mean of its divisors is an integer number (2021705156557).

Almost surely, 24043410313113 is an apocalyptic number.

It is an amenable number.

4043410313113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4043410313113 is an equidigital number, since it uses as much as digits as its factorization.

4043410313113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 4043410313113 its reverse (3113130143404), we get a palindrome (7156540456517).

The spelling of 4043410313113 in words is "four trillion, forty-three billion, four hundred ten million, three hundred thirteen thousand, one hundred thirteen".