Base | Representation |
---|---|
bin | 10010011000110101000110… |
… | …01100001010100111111001 |
3 | 12022011121020200220112211002 |
4 | 21030122203030022213321 |
5 | 20244444011324444433 |
6 | 221555501222414345 |
7 | 11342241605002064 |
oct | 1114324314124771 |
9 | 168147220815732 |
10 | 40435559999993 |
11 | 1197a696515814 |
12 | 46508232913b5 |
13 | 197409815b802 |
14 | 9db13d2bb8db |
15 | 4a1c4d4119e8 |
hex | 24c6a330a9f9 |
40435559999993 has 2 divisors, whose sum is σ = 40435559999994. Its totient is φ = 40435559999992.
The previous prime is 40435559999957. The next prime is 40435560000091. The reversal of 40435559999993 is 39999995553404.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 39932124340969 + 503435659024 = 6319187^2 + 709532^2 .
It is a cyclic number.
It is not a de Polignac number, because 40435559999993 - 210 = 40435559998969 is a prime.
It is not a weakly prime, because it can be changed into another prime (40435559999953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20217779999996 + 20217779999997.
It is an arithmetic number, because the mean of its divisors is an integer number (20217779999997).
Almost surely, 240435559999993 is an apocalyptic number.
It is an amenable number.
40435559999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
40435559999993 is an equidigital number, since it uses as much as digits as its factorization.
40435559999993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9565938000, while the sum is 83.
The spelling of 40435559999993 in words is "forty trillion, four hundred thirty-five billion, five hundred fifty-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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