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404395684313 is a prime number
BaseRepresentation
bin1011110001001111101…
…11000111000111011001
31102122211000211021021112
411320213313013013121
523111200243344223
6505435442550105
741134205413115
oct5704767070731
91378730737245
10404395684313
11146559904055
126645b368335
132c19921cb8a
1415803cb6745
15a7bc77d778
hex5e27dc71d9

404395684313 has 2 divisors, whose sum is σ = 404395684314. Its totient is φ = 404395684312.

The previous prime is 404395684291. The next prime is 404395684477. The reversal of 404395684313 is 313486593404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 380199259609 + 24196424704 = 616603^2 + 155552^2 .

It is a cyclic number.

It is not a de Polignac number, because 404395684313 - 218 = 404395422169 is a prime.

It is not a weakly prime, because it can be changed into another prime (404395684213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202197842156 + 202197842157.

It is an arithmetic number, because the mean of its divisors is an integer number (202197842157).

Almost surely, 2404395684313 is an apocalyptic number.

It is an amenable number.

404395684313 is a deficient number, since it is larger than the sum of its proper divisors (1).

404395684313 is an equidigital number, since it uses as much as digits as its factorization.

404395684313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3732480, while the sum is 50.

Subtracting from 404395684313 its reverse (313486593404), we obtain a palindrome (90909090909).

The spelling of 404395684313 in words is "four hundred four billion, three hundred ninety-five million, six hundred eighty-four thousand, three hundred thirteen".