40441411131133 has 4 divisors (see below), whose sum is σ = 40450266272800. Its totient is φ = 40432555989468.

The previous prime is 40441411131101. The next prime is 40441411131151. The reversal of 40441411131133 is 33113111414404.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 40441411131133 - 2⁵ = 40441411131101 is a prime.

It is a super-2 number, since 2×40441411131133² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40441411131095 and 40441411131104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40441411135133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4427563983 + ... + 4427573116.

It is an arithmetic number, because the mean of its divisors is an integer number (10112566568200).

Almost surely, 2^{40441411131133} is an apocalyptic number.

It is an amenable number.

40441411131133 is a deficient number, since it is larger than the sum of its proper divisors (8855141667).

40441411131133 is an equidigital number, since it uses as much as digits as its factorization.

40441411131133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8855141666.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 40441411131133 its reverse (33113111414404), we get a palindrome (73554522545537).

The spelling of 40441411131133 in words is "forty trillion, four hundred forty-one billion, four hundred eleven million, one hundred thirty-one thousand, one hundred thirty-three".