Base | Representation |
---|---|
bin | 100101101010101001… |
… | …101010101001001101 |
3 | 10212101121112202000100 |
4 | 211222221222221031 |
5 | 1130312131410013 |
6 | 30325115321313 |
7 | 2631145303506 |
oct | 455251525115 |
9 | 125347482010 |
10 | 40444013133 |
11 | 16174655747 |
12 | 7a08750239 |
13 | 3a77064224 |
14 | 1d5954bbad |
15 | 10ba991473 |
hex | 96aa6aa4d |
40444013133 has 12 divisors (see below), whose sum is σ = 59021390428. Its totient is φ = 26684709120.
The previous prime is 40444013101. The next prime is 40444013177. The reversal of 40444013133 is 33131044404.
40444013133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 21199942404 + 19244070729 = 145602^2 + 138723^2 .
It is not a de Polignac number, because 40444013133 - 25 = 40444013101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 40444013097 and 40444013106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40444013033) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23162938 + ... + 23164683.
Almost surely, 240444013133 is an apocalyptic number.
It is an amenable number.
40444013133 is a deficient number, since it is larger than the sum of its proper divisors (18577377295).
40444013133 is a wasteful number, since it uses less digits than its factorization.
40444013133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46327724 (or 46327721 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 40444013133 its reverse (33131044404), we get a palindrome (73575057537).
The spelling of 40444013133 in words is "forty billion, four hundred forty-four million, thirteen thousand, one hundred thirty-three".
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