Base | Representation |
---|---|
bin | 10010011001011001111001… |
… | …00000011111110111111111 |
3 | 12022020111020020222212020200 |
4 | 21030230330200133313333 |
5 | 20300304434400110101 |
6 | 222012525215014543 |
7 | 11343541230124605 |
oct | 1114547440376777 |
9 | 168214206885220 |
10 | 40455312113151 |
11 | 11988002024781 |
12 | 465461620a453 |
13 | 1975bc5383830 |
14 | 9dc0946b7875 |
15 | 4a2507514986 |
hex | 24cb3c81fdff |
40455312113151 has 24 divisors (see below), whose sum is σ = 62930766618720. Its totient is φ = 24895465477056.
The previous prime is 40455312113147. The next prime is 40455312113197. The reversal of 40455312113151 is 15131121355404.
40455312113151 is a `hidden beast` number, since 4 + 0 + 4 + 5 + 531 + 2 + 113 + 1 + 5 + 1 = 666.
It is not a de Polignac number, because 40455312113151 - 22 = 40455312113147 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40455312113351) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31145070 + ... + 32417988.
It is an arithmetic number, because the mean of its divisors is an integer number (2622115275780).
Almost surely, 240455312113151 is an apocalyptic number.
40455312113151 is a deficient number, since it is larger than the sum of its proper divisors (22475454505569).
40455312113151 is a wasteful number, since it uses less digits than its factorization.
40455312113151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1544575 (or 1544572 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 36.
Adding to 40455312113151 its reverse (15131121355404), we get a palindrome (55586433468555).
The spelling of 40455312113151 in words is "forty trillion, four hundred fifty-five billion, three hundred twelve million, one hundred thirteen thousand, one hundred fifty-one".
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