405014131 has 2 divisors, whose sum is σ = 405014132. Its totient is φ = 405014130.

The previous prime is 405014117. The next prime is 405014143. The reversal of 405014131 is 131410504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 405014131 - 2⁷ = 405014003 is a prime.

It is a super-3 number, since 3×405014131³ (a number of 27 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 405014099 and 405014108.

It is not a weakly prime, because it can be changed into another prime (405014111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202507065 + 202507066.

It is an arithmetic number, because the mean of its divisors is an integer number (202507066).

Almost surely, 2^405014131 is an apocalyptic number.

405014131 is a deficient number, since it is larger than the sum of its proper divisors (1).

405014131 is an equidigital number, since it uses as much as digits as its factorization.

405014131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 405014131 is about 20124.9628819533. The cubic root of 405014131 is about 739.8722271479.

Adding to 405014131 its reverse (131410504), we get a palindrome (536424635).

It can be divided in two parts, 4050 and 14131, that added together give a palindrome (18181).

The spelling of 405014131 in words is "four hundred five million, fourteen thousand, one hundred thirty-one".