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405045214353331 is a prime number
BaseRepresentation
bin101110000011000101111000…
…0000111101001011110110011
31222010010221111102011101002221
41130012023300013221132303
5411042230044333301311
63553243111440021511
7151213360001230546
oct13406136007513663
91863127442141087
10405045214353331
1110807278aaa5012
1239518586901897
13145017a4a64636
147204415cda85d
1531c624eed0671
hex17062f01e97b3

405045214353331 has 2 divisors, whose sum is σ = 405045214353332. Its totient is φ = 405045214353330.

The previous prime is 405045214353209. The next prime is 405045214353431. The reversal of 405045214353331 is 133353412540504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 405045214353331 - 243 = 396249121331123 is a prime.

It is a super-2 number, since 2×4050452143533312 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (405045214353431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202522607176665 + 202522607176666.

It is an arithmetic number, because the mean of its divisors is an integer number (202522607176666).

Almost surely, 2405045214353331 is an apocalyptic number.

405045214353331 is a deficient number, since it is larger than the sum of its proper divisors (1).

405045214353331 is an equidigital number, since it uses as much as digits as its factorization.

405045214353331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 405045214353331 its reverse (133353412540504), we get a palindrome (538398626893835).

The spelling of 405045214353331 in words is "four hundred five trillion, forty-five billion, two hundred fourteen million, three hundred fifty-three thousand, three hundred thirty-one".